SOLUTION: How can i find the y-intercept using x=0 in the quadratic y= 2x^-5x-3? do I use the formula -b/2a to find the vertex for x or y=ax^2+bx+c or both? I need very clear instructions fo

Question 555500: How can i find the y-intercept using x=0 in the quadratic y= 2x^-5x-3? do I use the formula -b/2a to find the vertex for x or y=ax^2+bx+c or both? I need very clear instructions for this because i simply don't understand, sorry.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
1)
To find the y-intercept, simply replace every x in the equation with 0 and evaluate.
Substitute x = 0.

The curve (a parabola) intercepts the y-axis at (0, -3).
2) To find the x-coordinate of the vertex, us where a = 2 and b = -5.
Evaluate.
or
Look at the graph of this equation:

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