SOLUTION: Use the discriminat to determine how many real number solutions the quadratic equation -4j^2 + 3j-28=0 has

Question 5545: Use the discriminat to determine how many real number solutions the quadratic equation -4j^2 + 3j-28=0 has
Answer by Abbey(339) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=457 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -2.29719479080399, 3.04719479080399. Here's your graph:

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