SOLUTION: If 9x+18 = 16x and bx = 99, what is the value of b?

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Question 550108: If 9x+18 = 16x and bx = 99, what is the value of b?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
First solve 9x%2B18=16x


9x%2B18=16x Start with the given equation.


9x=16x-18 Subtract 18 from both sides.


9x-16x=-18 Subtract 16x from both sides.


-7x=-18 Combine like terms on the left side.


x=%28-18%29%2F%28-7%29 Divide both sides by -7 to isolate x.


x=18%2F7 Reduce.

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So because bx=99, we know that b%2818%2F7%29=99. Now solve for b to get


18b+=+99%2A7


18b+=+693


b+=+693%2F18


b+=+77%2F2