# SOLUTION: Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they? Marie= x-4 Julie= x julie= (x+3) marie= x-4+3 = (x-1) (x+3)(x-1)

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they? Marie= x-4 Julie= x julie= (x+3) marie= x-4+3 = (x-1) (x+3)(x-1)      Log On

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 Click here to see ALL problems on Quadratic Equations Question 549585: Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they? Marie= x-4 Julie= x julie= (x+3) marie= x-4+3 = (x-1) (x+3)(x-1)= 410 Answer by stanbon(57974)   (Show Source): You can put this solution on YOUR website!Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they? Marie= x-4 Julie= x julie= (x+3) marie= x-4+3 = (x-1) (x+3)(x-1)= 410 ---- x^2+2x-413 = 0 --- Positive solution: x = [-2 + sqrt(4-4*-413)]/2 ----- x = [-2 + 40.69]/2 ----- x = 19.35 years (Julie's age now) x-4 = 15.35 years (Marie's age now) ---- Cheers, Stan H. ============