SOLUTION: Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they? Marie= x-4 Julie= x julie= (x+3) marie= x-4+3 = (x-1) (x+3)(x-1)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they? Marie= x-4 Julie= x julie= (x+3) marie= x-4+3 = (x-1) (x+3)(x-1)      Log On


   

Question 549585: Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they?
Marie= x-4
Julie= x
julie= (x+3)
marie= x-4+3 = (x-1)
(x+3)(x-1)= 410


Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Marie is 4 years younger than Julie. In 3 years the product of their ages will be 410. How old are they?
Marie= x-4
Julie= x
julie= (x+3)
marie= x-4+3 = (x-1)
(x+3)(x-1)= 410
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x^2+2x-413 = 0
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Positive solution:
x = [-2 + sqrt(4-4*-413)]/2
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x = [-2 + 40.69]/2
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x = 19.35 years (Julie's age now)
x-4 = 15.35 years (Marie's age now)
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Cheers,
Stan H.
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