SOLUTION: Solve the equation by making an appropriate substitution. x-512-16sqrtx=0 here is what I have tried: x^1-16x^1/2-512 (x^1/2)^2-16^1/2-512 subsitute x for u u^2-16u-512 facto

Question 542571: Solve the equation by making an appropriate substitution.
x-512-16sqrtx=0
here is what I have tried:
x^1-16x^1/2-512
(x^1/2)^2-16^1/2-512
subsitute x for u
u^2-16u-512
factor (I cannot find a factor for this problem so I divide everything by 2)
u^2-8u-256
using the formula
8 +-sqrt8^2-4(1)(256)/2(1)
8 +-sqrrt1088 / 2
reduced
4+12sqrrt17, 4-12sqrrt17
my answer choices are
{768}
{2068}
{1024}
{512}

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You're ok up the point of substituting or
This wil factor:
Apply the zero product rule.
or so...
or Substitute
or Square both sides in each case.
or
You should check these solutions because, in squaring, you may have inadvertently introduced invalid solutions.
Substitute

OK
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