SOLUTION: Two numbers differ by 7,the different of their squares is 91,find the numbers.

Algebra.Com
Question 542384: Two numbers differ by 7,the different of their squares is 91,find the numbers.
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
Two numbers differ by 7,the different of their squares is 91,find the numbers.
Two numbers: a, b
a - b = 7
a = (b+7)
:
a^2 - b^2 = 91
:
Replace a with (b+7)
(b+7)^2 - b^2 = 91
:
FOIL (b+7)(b+7)
b^2 + 14b + 49 - b^2 = 91
b^2 - b^2 + 14b = 91 - 49
14b = 42
b = 42/14
b = 3
:
Find a
a = 3 + 7
a = 10
:
:
Check: 10^2 - 3^2 = 91

RELATED QUESTIONS

two numbers differ by 7 and the sum of their squares is 29. find the numbers (answered by JBarnum,Stitch)
two positive numbers differ by 7 and the sum of their squares is 169. find the numbers. (answered by Tatiana_Stebko)
two numbers differ by 2. The sum. of their squares is 244.find the numbers (answered by addingup,MathTherapy)
Two positive numbers differ by 6, and their squares differ by 96. Find the... (answered by ankor@dixie-net.com)
two numbers differ by 8 and the sum of their squares is 320. find the two... (answered by drk)
two numbers differ by 9. the sum of their squares is 653. what are the... (answered by josgarithmetic)
Two positive numbers differ by 5 and the squares of their sum is 169. Find the... (answered by sofiyac)
Two numbers differ by 3 . The sum of their reciprocal is 7/10 find the... (answered by stanbon,josmiceli)
two positive numbers differ by 4 and square of their sum is 324. Find the... (answered by josgarithmetic)