Find the value of Q P + R = 4 QP + R = 10 P + QR = 14 This is a system of 3 equations in 3 unknowns. Solve the first equation for P P = 4 - R Substitute (4 - R) for P in the 2nd equation: QP + R = 10 Q(4 - R) + R = 10 4Q - QR + R = 10 Substitute (4 - R) for P in the 3rd equation: P + QR = 14 (4 - R) + QR = 14 4 - R + QR = 14 -R + QR = 10 Now we have this system of two equations in 2 unknowns 4Q - QR + R = 10 -R + QR = 10 Now we write the terms on the left of the second equation in the opposite order, draw a line and add vertically term by term: 4Q - QR + R = 10 QR - R = 10 ---------------- 4Q = 20 Q = 5 Substitute 5 for Q in the equation QR - R = 10: QR - R = 10 5R - R = 10 4R = 10 R = 10/4 R = 5/2 Substitute 5/2 for R in the equation P = 4 - R: P = 4 - R P = 4 - 5/2 P = 8/2 - 5/2 P = 3/2 So (P, Q, R) = (3/2, 5, 5/2) Edwin