# SOLUTION: Please help me solve these: 2x^2-x-28=0 x^2-2x=15 2x(x+7)(x+4)=0 x(x-5)=-6 x^2=16x

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 Question 535691: Please help me solve these: 2x^2-x-28=0 x^2-2x=15 2x(x+7)(x+4)=0 x(x-5)=-6 x^2=16xAnswer by Earlsdon(6287)   (Show Source): You can put this solution on YOUR website!There are four ways you can solve quadratic equations: 1) Use the quadratic formula: 2) Completing the square. 3) Factoring. 4) Use algebraic methods. In problems 1 through 4, you can use factoring and in problem 5, use algebra: 1) Factor. Apply the zero product rule. or so that or so 2) Subtract 15 from both sides. Factor. Apply the zero product rule. or so that... or 3) This is already factored so apply the zero product rule. or or so that... or or 4) Expand the left side. Add 6 to both sides. Factor. Apply the zero product rule. or so that... or 5) Use algebra. Divide both sides by x.