SOLUTION: Find the vertex the line of symmetry, the maximum or minimum value of the f(x). Graph the function. f(x)= 1/4(x+2)^2+4

Question 534399: Find the vertex the line of symmetry, the maximum or minimum value of the f(x). Graph the function.
f(x)= 1/4(x+2)^2+4

Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
f(x) = 1/4(x+2)^2 +4
f(x) = 1/4(x^2 +4x + 4) + 4
f(x) = 1/4*x^2 +x + 5
.
axis of symmetry = -b/2a
-b/2a = -1/(2*1/4) = -1/(1/2) = -2
vertex = 1/4(-2+2)^2 +4 = 4
(-2,4)
.

RELATED QUESTIONS
Graph the function. Find the vertex, line of symmetry, and maximum or minimum value.... (answered by lwsshak3)

Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph... (answered by ewatrrr)

Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph... (answered by Alan3354)

find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph... (answered by robertb)

Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph... (answered by stanbon)

Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the (answered by lwsshak3)

Find the vertex, the line of symmetry, and the maximum or minimum value of f(x). Graph... (answered by ewatrrr)