SOLUTION: How do you derive the formula 1/2(n^2-n+2 using an^2+bn+c?
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Question 530298: How do you derive the formula 1/2(n^2-n+2 using an^2+bn+c?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do you derive the formula 1/2(n^2-n+2) using an^2+bn+c?
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(1/2)n^2 - (1/2)n + 1
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n = [(1/2) +- sqrt((1/4)-4*(1/2)*1)]/1
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etc.
Cheers,
Stan H.
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