SOLUTION: Solve each equation by using the quadratic formula. 3a^2-4a=-5

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Question 526676: Solve each equation by using the quadratic formula.
3a^2-4a=-5
Found 2 solutions by oberobic, stanbon:
Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -44 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -44 is + or - .

The solution is

Here's your graph:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Solve each equation by using the quadratic formula.
3a^2-4a=-5
----
3a^2-4a+5 = 0
---
a = [4 +- sqrt(16-4*3*5)]/6
----
a = [4 +- sqrt(-44)]/6
-----
a = [4+- 2*sqrt(11)]/6
---
a = (2/3)+-(1/3)sqrt(11)
===========================
Cheers,
Stan H.
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