SOLUTION: I am lost here, can someone help me?
Find the x-intercepts
y=x^2-4x+4
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Question 52345This question is from textbook Beginnning Algebra
: I am lost here, can someone help me?
Find the x-intercepts
y=x^2-4x+4
This question is from textbook Beginnning Algebra
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
You find x intercepts by letting y=0 and solving for x. For this one let y=0, factor, then set each parenthese =0 and solve for x.
y=x^2-4x+4
0=(x-2)(x-2)
0=x-2
0+2=x-2+2
2=x
Since this is a perfect square trinomial, there is only one x-intercept.
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