SOLUTION: (2y+3)^2-7=0 using the square root property. Sqrt (3-x) ) -7=0 Sqrt (x+5) )= 7-x Simplify 2 sqrt (75))- 5 sqrt (27))- sqrt (48))

Question 520931: (2y+3)^2-7=0 using the square root property.
Sqrt (3-x) ) -7=0
Sqrt (x+5) )= 7-x
Simplify 2 sqrt (75))- 5 sqrt (27))- sqrt (48))
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
(2y+3)^2-7=0 using the square root property.
(2y+3)^2=7
2y+3=+-sqrt(7)
2y=-3+-sqrt(7)
y=(-3+-sqrt(7))/2
.
Ed

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