SOLUTION: Find b2 – 4ac and the number of real solutions for the given equation.
16-24+9x^2=0
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Question 510959: Find b2 – 4ac and the number of real solutions for the given equation.
16-24+9x^2=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find b2 – 4ac and the number of real solutions for the given equation.
16-24x+9x^2=0
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a = 9 ; b = -24 ; c = 16
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b^2 - 4ac = 24^2 - 4*9*16 = 0
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Since b^2-4ac = 0 there are 2 equal Real Number solutions.
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Cheers,
Stan H.
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