SOLUTION: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.

Question 51014: The length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Found 2 solutions by Juhi, Niku:
Answer by Juhi(44) (Show Source): You can put this solution on YOUR website!
width=x
length=2x+2
Perimeter= 2(2x+2+x)
52=4x+4+2x
48=6x
8=x
width= 8 cm
length= 18 cm

Answer by Niku(6) (Show Source): You can put this solution on YOUR website!
width=x
length= 2x+2
Perimeter=2(length + width)
52 cm= 2(2x+2+x)
52 cm=4x+4+2x
48 cm=6x
8 cm= width
18 cm= length
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