SOLUTION: Solve the equation 4x^2 +12x=0 f(x) =4x^2+12x=0 where c is a constant And part b Given that f(x) =0 has equal roots find value of c and hence solve f(x) =0

SOLUTION: Solve the equation 4x^2 +12x=0 f(x) =4x^2+12x=0 where c is a constant And part b Given that f(x) =0 has equal roots find value of c and hence solve f(x) =0

Algebra.Com

Question 509230: Solve the equation 4x^2 +12x=0
f(x) =4x^2+12x=0 where c is a constant
And part b
Given that f(x) =0 has equal roots find value of c and hence solve f(x) =0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Your question as posed makes very little sense. I think you have left out some things.

If you simply solve

, you simply factor out

to get

giving you roots of 0 and -3.

But your statement:

makes no sense at all. Either

or

.

I suspect that what you are really looking for is: Given

and the fact that the roots of

are real and equal, find

Recalling the quadratic formula and the process of evaluating the discriminant, if the discriminant (

) is equal to zero, then the zeros of the quadratic function are real and equal.

So, noting that

,

, and

Solve

for

John

My calculator said it, I believe it, that settles it

The Out Campaign: Scarlet Letter of Atheism

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