SOLUTION: I am trying to find the time it takes for an object to reach 180 ft. I have h = -16t^2 + 112t. The velocity is 112 ft/s, so I need to solve it as 16t^2 + 112t = 180

Algebra.Com
Question 50420This question is from textbook
: I am trying to find the time it takes for an object to reach 180 ft. I have h = -16t^2 + 112t. The velocity is 112 ft/s, so I need to solve it as 16t^2 + 112t = 180 This question is from textbook

Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!
I am trying to find the time it takes for an object to reach 180 ft. I have h = -16t^2 + 112t. The velocity is 112 ft/s, so I need to solve it as 16t^2 + 112t = 180
16T^2+112T-180=0...DIVIDE WITH 4
4T^2+28T-45=0

T=[-28+SQRT{28^2-4*4*(-45)}]/8=1.3477

RELATED QUESTIONS

Science and medicine. The equation {{{h= -16t^2+112t}}} gives the hight of an arrow, shot (answered by ankor@dixie-net.com)
Please help me with this...I can not figure this out. Science and medicine: The... (answered by tutorcecilia)
The equation gives the height of an arrow, shot upward from the ground with an initial... (answered by ankor@dixie-net.com)
Science and medicine: The equation h = -16t^2 + 112t gives the height of an arrow, shot (answered by jim_thompson5910)
Science and medicine. The equation h=-16t^2+112t gives the height of an arrow, shot... (answered by Earlsdon,stanbon)
the equation h=16t^2+112t gives the height of an arrow. shot upward from the ground with... (answered by tutorcecilia)
The equation h = -16t^2 + 112t gives the height of an arrow, shot upward from the ground... (answered by Nate)
The equation h=-16t^2 + 112t gives the height of an arrow, shot upward from the ground... (answered by ankor@dixie-net.com)
Science and medicine. The equation h= -16t^2 + 112t gives the height of an arrow, shot... (answered by ankor@dixie-net.com)