SOLUTION: I think I am supposed to solve by factoring:x^2+4x+4=7. I first subtracted 7 from both sides for x^2+4x-3=0. Can you assist please?

Question 49826This question is from textbook
: I think I am supposed to solve by factoring:x^2+4x+4=7. I first subtracted 7 from both sides for x^2+4x-3=0. Can you assist please? This question is from textbook

Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Are you good at factoring by now? If not, see my Lesson Plans on Algebra.com or on my website that have to do with factoring. If you need help finding them, send me an Email.

Now, back to the factoring:

It has to start out with x times x and look like this:
(x _____)(x______)

Next, look at the last term, which is a -3. The middle term is 4x.
What times what would be -3 that would add up to 4 for the middle term.

The reason you were having trouble factoring this is because it does NOT factor. What I did notice is that in the original problem, the is a perfect square trinomial, so let's do it this way:

Take the square root of each side:

Last, subtract 2 from each side:

R^2 at SCC
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