SOLUTION: (x-2)(x-3)>=0 where x cannot be equal to 2. and the answer is (2,3] here two is included and three is not. Now if i put 2 in the above equation: (2-2)(2-3) (0)(-1) which is

Question 489559: (x-2)(x-3)>=0
where x cannot be equal to 2.
and the answer is (2,3] here two is included and three is not.
Now if i put 2 in the above equation:
(2-2)(2-3)
(0)(-1) which is equal to zero
and if i put x=3 then
(3-2)(3-3)
(1)(0) which is also equal to zero
So why 2 is not included in the answer and 3 is.
Answer by chessace(471) (Show Source): You can put this solution on YOUR website!
Double check the wording.
If "where x cannot be equal to 2" is specified in the problem, that explains why 2 is excluded even though it is just as good as 3.
Also,
"the answer is (2,3] here two is included and three is not."
is backwards, this notation excludes 2 and includes 3.
Also,
(x-2)(x-3)>=0
Looks like a typo in that the given solution would be quite wrong for it, but right for (x-2)(x-3)<=0

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