SOLUTION: An object is thrown upward from the top of a 160 foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic
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Question 480853: An object is thrown upward from the top of a 160 foot building with an initial velocity of 48 feet per second. The height h of the object after t seconds is given by the quadratic equation h= 16t2+48t+160. When will the object hit the ground?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
h=0 when it reaches the terrace height on its way down
solve using quadratic formula
The square root is negative which is absurd.
The equation should be
a = -1,b = 3,c = 10
(ignore negative number)
t = 5
The object will hit the ground in 5 sec
m.ananth@hotmail.ca
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