SOLUTION: i need help with this quadratic using the formula.. i did the work and my answer came out to be irrational is this true? a=3x^2+ b=8x+ c=2

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Question 47789: i need help with this quadratic using the formula.. i did the work and my answer came out to be irrational is this true?
a=3x^2+
b=8x+
c=2
Found 2 solutions by stanbon, venugopalramana:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
a=3x^2+
b=8x+
c=2
----------------------
The a,b,and c are the coefficients of the terms,
not the terms themselves.
a=3
b=8
c=2
----------
Then the determinant is b^2-4ac = 64-4*3*2=40
Since this is greater than zero the quadratic has
two real zeroes. The zeroes may be irrational and
still be real.
Consider the following:
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=40 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: -0.279240779943873, -2.38742588672279. Here's your graph:

Hope this helps.
Cheers,
Stan H.


























Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!
i need help with this quadratic using the formula.. i did the work and my answer came out to be irrational is this true?
a=3x^2+
b=8x+
c=2
3x^2+8x+2=0





yes you are correct.the roots are irrational
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