Hi,

Find the vertex and axis of the parabola y-4=-2(x+3)^2

*Using the vertex form of a parabola,  where(h,k) is the vertex

y-4=-2(x+3)^2 Green

y = -2(x+3)^2 + 4  |vertex (-3,4), line of symmetry is x = -3

 a = -2 < 0, Parabola opens downward, Vertex is a maximum point



parabola having vertex (-2,1) and containing the point (-3,4). 

* y = a(x+2)^2 + 1, 4 = a(-3+2)^2 + 1, a = 3, y = 3(x+2)^2 + 1  Blue

* f(x) = 2x^2 + 12x+7, f(x) = 2(x+3)^2 -11 Purple V(-3,-11) x = -3

* f(x) = 2x^2 + 6x + 5, f(x) = 2(x+3/2)^2 + 1/2, a = 2>0, V(-3/2,)min Yellow



 9. Find a quadratic equation with integral coefficients (integers) having roots: ,

 (x-5/2)(x+5/2) = 0, x^2 - 25/4 = 0, y = x^2 - 25/4

A rectangular corral is made with a total of 100 feet of fencing on three sides. The fourth side is the side of a barn. 

The greatest possible area for the enclosure would be square: 3s = 100, s = 33 1/3ft 

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