SOLUTION: Find the Logarithm:
log2(logb(SQRE ROTb))
The 2 and b is the undersub
Please show me step by step to get the answer. Thanks
Algebra.Com
Question 475619: Find the Logarithm:
log2(logb(SQRE ROTb))
The 2 and b is the undersub
Please show me step by step to get the answer. Thanks
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log2(logb(Sqrt(b))
----
= log2[(1/2)logb(b))
-------
log2(1/2)
---
= -1
=============
cheers,
Stan H.
RELATED QUESTIONS
Simplify as much as possible: SQRE ROOT 27+ 2 SQRE ROOT12 + SQRE ROOT 3
I got the... (answered by ewatrrr)
Solve: SQRE ROOT x-5=x-5
I got the answer (5,6) but I don't know how
Please show me (answered by jorel1380,Alan3354)
Simplify:
b^-1 + c^-1
Please show me step by step to get the answer.... (answered by stanbon)
Simplify:
(b^4c^-7)^-5
Please show me step by step to get the answer.... (answered by Alan3354)
Simplify:
(b^5)^-8
Please show me step by step to get the answer.... (answered by Alan3354,richard1234)
Solve:
12t-36=t^2
Please show me step by step to get the answer.... (answered by stanbon)
Simplify:
3^-2
Please show me step by step to get the answer.... (answered by stanbon)
Simplify: Assume that b and c are positive.
b^2/5(b^8/5 + b^3/5)
Please show me... (answered by MathLover1)
Simplify: Assume that b and c are positive.
(8b^2/3 / 2b^4/5)^3/2
Please show me... (answered by stanbon)