Hi,

Using the vertex form of a parabola,  where(h,k) is the vertex

f(x)=1/5(x+4)^2+3 

Vertex is (-4,3) Line of symmetry is x = -4

 a = 1/5, a>0   Parabola opens upward, Vertex is a minimum Pt.  f(x) = 3



 

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