SOLUTION: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function. f(x)=-4(x+8)^2 +2

Question 473447: Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function.
f(x)=-4(x+8)^2 +2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Find the vertex, the line of symmetry and the maximum or minimum value of f(x). Graph the function.
f(x)=-4(x+8)^2 +2
**
Standard for a parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. A is a multiplier which affects the steepness of the curve.
For given equation:
f(x)=-4(x+8)^2 +2
This is a parabola with the vertex at (-8,2).
The lead coefficient being negative means the parabola opens downward, and it has a maximum value of 2. The axis of symmetry is y=-8
See the graph below as a visual check on the answers:
..

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