SOLUTION: During the first part of a trip, a canoeist travels 88 miles at a certain speed. The canoeist travels 19 miles on the second part of the trip at a speed 5mph slower. The total time
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Question 471343: During the first part of a trip, a canoeist travels 88 miles at a certain speed. The canoeist travels 19 miles on the second part of the trip at a speed 5mph slower. The total time for the trip is 2 hrs. What was the speed on each part of the trip?
1.Speed of 1st part of the trip?
2.Speed of 2nd part of the trip?''.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
speed in first part x mph
speed second part x -5 mph
Total rowing time 2 hours
Time first part 88 / x
Time second part19/(x-5)
Time first part + time second part = 2 hours
88/x + 19 /(x -5 ) = 2
LCD = ( x + 0 )* (x -5 )
multiply the equation by the LCD
we get
88*(x-5)+19x= 2
88x-440 +19x=2X^2-10
117x-440=2X^2
2 X^2 -117 x 440 = 0
2 X^2+ -117 x+ 440 =
/ 2
1 X^2 -58.5 x 220 =
Find the roots of the equation by quadratic formula
a= 1 b= -58.5 c= 220
b^2-4ac= 3422.25 - -880
b^2-4ac= 2542.25
= 50.42
x1=( 58.5 + 50.42 )/ 2
x1= 54.46 54 4/9
x2=( 58.5 -50.42 ) / 2
x2= 4.04 4
Ignore value
x = 54.46 mph
m.ananth@hotmail.ca
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