SOLUTION: I am stuck on 3 last questions for my practice exam and was hoping someone can show me steps to take to solve these problems. I do not expect answers, I just do not understand the

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Question 471220: I am stuck on 3 last questions for my practice exam and was hoping someone can show me steps to take to solve these problems. I do not expect answers, I just do not understand the steps to take. Please help!
Solve:
x^2+2x-4=0
b^2+3b-10=0
r^2-5r-24=0

Found 2 solutions by MathLover1, jorel1380:
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

Solve:..to do it, simplest way is to use quadratic formula
1.

...note that , and








solutions:




or





2.







solutions:



or



3.











solutions:






or









Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
x2+2x-4=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=20 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 1.23606797749979, -3.23606797749979. Here's your graph:

--------------
b2+3b-10=0
(b+5)(b-2)=0
b=-5 or 2
------------
r2-5r-24=0
(r-8)(r+3)=0
r=8 or -3..

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