Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation For these solutions to exist, the discriminant First, we need to compute the discriminant Discriminant d=64 is greater than zero. That means that there are two solutions: Quadratic expression Again, the answer is: -4, -12. Here's your graph: |
Hi,
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Following all do relate to:
the vertex form of a parabola opening up or down,
where(h,k) is the vertex. a> 0 Vertex a minimum point. a<0 Vertex a maximum Pt
3) f(x)=-(x+2)^2-7 V(-2,-7) -1<0 Maximum Pt x = -2 Line of symmetry
7) f(x)=1/3(x+2)^2+3 V(-2,3) 1/3>0 Minimum Pt x = -2 Line of symmetry
12) f(x)=-3(x+2)^2 V(-2,0) -3<0 Maximum Pt x = -2 Line of symmetry
13) f(x)=1/4 x^2 V(0,0) 1/4>0 Minimum Pt Pt x = 0(y-axis) Line of symmetry
following involve completing the Square
15) f(x)=x^2-8x-4
f(x) = 1*(x-4)^2 -20 V(4,-20) 1>0 Minimum Pt x = 4 Line of symmetry
17) f(x)=3x^2-6x+6
f(x) = 3(x-1)^2 +3 V(1,3) 3>0 Maximum Pt x = 1 Line of symmetry
20) f(x)=2x^2+2x+10
f(x)= 2(x+1/2)^2 + 9.5 V(-1/2,9.5) 2>0 Minimum Pt x = -1/2 Line of symmetry