Hi,

Using the vertex form of a parabola,  where(h,k) is the vertex

f(x)= -x^2+6x+6

f(x)= -[(x-3)^2 -9]+6

f(x)= -(x-3)^2 +15  V(3,15) maximum  a = -1 a<0 Parabola opens downward

                    Line of symmetry x = 3



f(x)= 2-x^2

f(x)= -(x-0)^2 + 2  V(0,2) maximum  a = -1 a<0  Parabola opens downward

                    Line of symmetry x = 0  (y-axis)





 

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