Let x be one number Let z be the other number Their difference is |x-z| |x-z| = 16 Case 1: Case 2: x-z = 16 or x-z=-16 -z = 16-x -z=-16-x z = -16+x z=16+x z = x-16 z=x+16 Let y be their product zx y = zx ------------------------------ In case 1: y = x(x-16) y = x²-16x Vertex formula theorem: y = ax+bx+c has a minimum value when x = -b/a if a > 0 y = ax+bx+c has a maximum value when x = -b/a if a < 0 y = x²-16x or y = 1x²-16x+0 a = 1, b = -16, c = 0 y = 1x-16x+0 has a minimum value when x = -(-16)/1 = 16 since a = 1 > 0 z = 16-16 = 0 So the numbers are 16 and 0 --------------- In case 2: y = x(x+16) y = x²+16x Vertex formula theorem: y = ax+bx+c has a minimum value when x = -b/a if a > 0 y = ax+bx+c has a maximum value when x = -b/a if a < 0 y = x²+16x or y = 1x²+16x+0 a = 1, b = 16, c = 0 y = 1x+16x+0 has a minimum value when x = -16/1 = -16 since a = 1 > 0 z = x+16 = -16+16 = 0 So the numbers are 0 and -16 ---------------------- So there are two possibilities, The two numbers could be 16 and 0 or else they could be 0 and -16 Edwin