SOLUTION: Find 2 numbers whose difference is 16 and whose product is minimun

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Question 466614: Find 2 numbers whose difference is 16 and whose product is minimun
Found 2 solutions by Edwin McCravy, Gogonati:
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
Let x be one number
Let z be the other number
Their difference is |x-z|
|x-z| = 16

Case 1:               Case 2:
x-z = 16       or     x-z=-16 
 -z = 16-x             -z=-16-x 
  z = -16+x             z=16+x 
  z = x-16              z=x+16
  

Let y be their product zx

y = zx

------------------------------

In case 1:

y = x(x-16)

y = x²-16x

Vertex formula theorem:

y = ax+bx+c has a minimum value when x = -b/a if a > 0
y = ax+bx+c has a maximum value when x = -b/a if a < 0

y = x²-16x

or

y = 1x²-16x+0

a = 1, b = -16, c = 0

y = 1x-16x+0 has a minimum value when x = -(-16)/1 = 16 since a = 1 > 0

z = 16-16 = 0

So the numbers are 16 and 0

---------------

In case 2:

y = x(x+16)

y = x²+16x

Vertex formula theorem:

y = ax+bx+c has a minimum value when x = -b/a if a > 0
y = ax+bx+c has a maximum value when x = -b/a if a < 0

y = x²+16x

or

y = 1x²+16x+0

a = 1, b = 16, c = 0

y = 1x+16x+0 has a minimum value when x = -16/1 = -16 since a = 1 > 0

z = x+16 = -16+16 = 0

So the numbers are 0 and -16 

----------------------

So there are two possibilities,

The two numbers could be 16 and 0 or else they could be 0 and -16

Edwin


Answer by Gogonati(855)   (Show Source): You can put this solution on YOUR website!
Let = x the first number, then the other number is x+16, and their product is the
function f(x)=x(x+16). The graph of this function is an upward parabola, where the
y-coordinate of its vertex is the minimum value of the function.
Write the equation of the parabola in standard form:
, from the final equation we see that the vertex is:
(-8, -64). Therefore two numbers are -8 and -8+16=8, where their difference is
8-(-8)=16, and their minimum product is -64.

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