SOLUTION: How does one find the particular equation of the quadratic function that passes through a vertex of (5, -1) and the point (8, -28)?

Question 4633: How does one find the particular equation of the quadratic function that passes through a vertex of (5, -1) and the point (8, -28)?
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
depends how much maths you know :-)

General quadratic is . Put in both sets of (x,y) to get 2 equations in a and b. Solve these and ten re-write the general equation.

Alternatively, if you know calculus, the gradient, dy/dx of the general equation is 2ax+b. At the vertex, the gradient is zero, so put that into the equation and the x-value, and you get that 10a+b=0. Then put the values of the other point into the QUADRATIC general equation and use the fact that b=-10a, to find a.

Both methods are much the same. Take your pick.

jon.
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