SOLUTION: find the vertex, line of symmetry, and maximum or minimum value of the quadratic function: f(x)= -2x^2 + 2x + 10
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Question 458254: find the vertex, line of symmetry, and maximum or minimum value of the quadratic function: f(x)= -2x^2 + 2x + 10
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Given the quadratic function
\ =\ ax^2\ +\ bx\ +\ c)
The 
-coordinate of the vertex is:
The 
-coordinate of the vertex is:
\ =\ a(x_v)^2\ +\ b(x_v)\ +\ c)
The axis of symmetry is
The lead coefficient is negative, hence the parabola opens downward, hence the vertex is a maximum, and the maximum value is the value of the function (read -coordinate) at the vertex.
John
My calculator said it, I believe it, that settles it
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