SOLUTION: find the vertex, line of symmetry , and maximum or minimum value of the quadratic function: f(x)= 2x^2

SOLUTION: find the vertex, line of symmetry , and maximum or minimum value of the quadratic function: f(x)= 2x^2 - 8x + 22

Question 458252: find the vertex, line of symmetry , and maximum or minimum value of the quadratic function: f(x)= 2x^2 - 8x + 22
Found 2 solutions by Alan3354, rfer:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The LOS is x = -b/2a
x = 8/4 = 2
x = 2 is the LOS
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The vertex is on the LOS
f(2) = 8 - 16 + 22 = 14
Vertex at (2,14)
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The vertex is the minimum

Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
vertex (2,14)minimum
axis=2
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