SOLUTION: Graph the Parabolas y=-2x^2+3x+2

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Question 458034: Graph the Parabolas y=-2x^2+3x+2
Answer by poliphob3.14(115)   (Show Source): You can put this solution on YOUR website!
Since a=-2 the parabola opens down. We know that the coordinates of vertex is the point: (x=-b/2a=-3/-4=3/4, and y=f(3/4)=-2*(3/4)^2+3*3/4+2=25/8), (3/4, 25/8)
Since , the graph intersect the x-axis at x=2 and
x=-1/2.
See the graph below:
.

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