Hi

y=x^2-9x+18

Note: the vertex form of a parabola,  where(h,k) is the vertex

y=x^2-9x +18   |Completing the square

y = [(x-4.5)^2 - 20.25] +18

y = (x-4.5)^2 - 2.25   Vertex(4.5,-2.25) a = 1 > 0 parabola opens upward

x-intercepts when y = 0 are also the solutions for the quadratic equation

 (x-4.5)^2 = 2.25

    x-4.5 = ± 

        x = 6 or x = 3

OR

 x^2 - 9x + 18 = 0  Using Quadratic Formula to solve for x

 

 

   x = 4.5 ± 1.5   x = 6 or x = 3



   

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