SOLUTION: I am having trouble with this problem I have gotten about half way through and can not figure out the rest.
Use the quadratic formula to solve each equation.
900x^2 - 8,100x =
Algebra.Com
Question 44696This question is from textbook Intermediate Algebra
: I am having trouble with this problem I have gotten about half way through and can not figure out the rest.
Use the quadratic formula to solve each equation.
900x^2 - 8,100x = 1,800
This is what I have come up with so far, Maybe I am making a mistake that I am overlooking.
900x^2/90 - 8,100x/90 = 1,800/90
10x^2 - 90x = 20
10x^2 - 90x - 20 = 0
AMP Parsing Error of [ x = [-(-90)+plus_minus-sqrt((-90)^2 - 4(10)(-20))]/2(10) ]: Invalid expression '[-(-90)+plus_minus-sqrt((-90)^2-4(10)(-20))]/2(10)': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203.
.
AMP Parsing Error of [ x = [-(-90)+plus_minus-sqrt(8,100 + 800)/20 ]: Invalid expression '[-(-90)+plus_minus-sqrt(8,100+800)/20': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203.
.
AMP Parsing Error of [ x = [-(-90)+plus_minus-sqrt(8,900)/20 ]: Invalid expression '[-(-90)+plus_minus-sqrt(8,900)/20': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203.
.
This is where I have gotten stuck.
I hope this problem is readable, I am having trouble figuring out the right way to type it on here.
Thanks in advance for any help you can provide me.
This question is from textbook Intermediate Algebra
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
900x^2 - 8,100x = 1,800
Divide both sides by 900 to get:
x^2-9x=2
x^2-9x-2=0
x=[9+sqrt(81+8)]/2 or x=[9-sqrt(90)]/2
Simplify a little to get:
x=[9+3sqrt10]/2 or x=[9-3sqrt(10)]/2
Cheers,
Stan H.
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