SOLUTION: If the area of a rectangle is 91m^2, and the dimensions are (x+2)m and (2x+3)m what is the value of x. I need to use the quadratic equation to find the value of x.

Question 444153: If the area of a rectangle is 91m^2, and the dimensions are (x+2)m and (2x+3)m what is the value of x. I need to use the quadratic equation to find the value of x.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
(x+2)m * (2x+3)m=91
x(2x+3)+2(2x+3)=91
2x^2+3x+4x+6=91
2x^2+7x-85=0
Find the roots of the equation by quadratic formula

a= 2 b= 7 c= -85

b^2-4ac=49+680
b^2-4ac=729
sqrt(729)=27

x1=(-7+27)/4
x1=5
x2=(-7-27)/4
x2= -8.5

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