SOLUTION: Solve the equation 7y3 - 14y2 + 6y = 0 by first factoring out the common factor y and then using the quadratic formula. (Enter solutions from smallest to largest. If there are any
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Question 442641: Solve the equation 7y3 - 14y2 + 6y = 0 by first factoring out the common factor y and then using the quadratic formula. (Enter solutions from smallest to largest. If there are any unused answer boxes, enter NONE in the last boxes.)
y = ?
y = ?
y = ?
Please show me the steps to get the answer. Thanks
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
7y3 - 14y2 + 6y = 0
y(7y^2-14y+6)=0
y=0
Find the roots of the equation by quadratic formula
a= 7 b= -14 c= 6
b^2-4ac=196-168
b^2-4ac=28,
= 5.29
y1=(14+5.29)/14
y1=1.38
y2=(14-5.29) / 14
y2= 0.62
...
y=0
y=1.38
y=0.62
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