SOLUTION: Please I need some extra help with this problems!! Graphing Parabolas, for example this y= -x^2-2x+1? please explain me how you do it? Thanks, Brian

Question 439903: Please I need some extra help with this problems!!
Graphing Parabolas, for example this y= -x^2-2x+1?
please explain me how you do it?
Thanks, Brian

Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Graphing Parabolas, for example this y= -x^2-2x+1?
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If you don't know much about quadratics and parabolas
the best you can do is plot points.
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If you know somethings you could find the y-intercept (0,1);
you could find the x-intercepts by solving -x^2-2x+1 = 0;
you could find the vertex at (-b/(2a),f(-b/(2a));
you could notice the parabola opens downward because the
coefficient of x^2 is negative.
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Cheers,
Stan H.
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
Graphing the parabola:
1. Determine whether the parabola opens or .
a. If , it opens .
b. If , it opens .
2. Determine the .
a. The is
b. The is found by substituting the in the equation .
3. Determine the by setting .
4. Determine the (if any) by setting ,or solving the equation
.
5. Determine two or three other points if there are no

.example:

1. , it opens
2. the .
a. The is
b. substitute the in the equation

the is at (-1,2)
3. Determine the by setting .

4. Determine the (if any) by setting ,or solving the equation

.use quadratic formula

or

5. Determine two or three other points if there are no
since you have , you skip this step

let see the graph:

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