SOLUTION: Adjacent sides of a rectangle differ by 5 ft. If the area of the rectangle is 84 sqft., what is the length of the smaller side? Thanks!!
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Question 439455: Adjacent sides of a rectangle differ by 5 ft. If the area of the rectangle is 84 sqft., what is the length of the smaller side? Thanks!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Adjacent sides of a rectangle differ by 5 ft. If the area of the rectangle is 84 sqft., what is the length of the smaller side?
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Let smaller side be "x":
Then larger side is "x+5":
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Area = (1/2)x(x+5)
84 = (1/2)(x^2+5x)
x^2 + 5x - 168 = 0
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x = [-5 +- sqrt(25-4*-168)]/2
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x = [-5 +-sqrt(697)]/2
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Positive solution:
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x = [21.4]/2
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x = 10.7 ft
x+5 = 15.7 ft.
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cheers,
Stan H.
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