SOLUTION: trying to factor 2x^3+7x^2-3x-18 completely given that x+2 is a factor. Tried to factor the first 3 numbers and the last three but getting stuck and don't understand how x+2 fits

Question 436722: trying to factor 2x^3+7x^2-3x-18 completely given that x+2 is a factor. Tried to factor the first 3 numbers and the last three but getting stuck and don't understand how x+2 fits in. Help! (and thanks!)
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
using either long or synthetic division, dividing 2x^3+7x^2-3x-18 by x+2 gives ___ 2x^2 + 3x - 9

2x^2 + 3x - 9 factors to ___ (2x - 3)(x + 3)

so the factors of 2x^3+7x^2-3x-18 are ___ (x + 2)(2x - 3)(x + 3)
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