SOLUTION: solve the quadratic equation x squared+4x-5=0 by completing squares.
{{{x^2 + 4x - 5 = 0}}}
Algebra.Com
Question 4350: solve the quadratic equation x squared+4x-5=0 by completing squares.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
Begin by adding 5 to each side to set up the "completing the square" process.
Take half of the 4 and square, which is 2 squared, or 4. Add 4 to each side of the equation to create a perfect square trinomial on the left side.
Take the square root of both sides:
Subtract 2 from each side:
In the first case, x = -2 + 3 = 1
In the second case, x = -2 - 3 = -5
Check answers:
For x = 1,
For x = -5,
Both answers check!
R^2 at SCC
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