Hi

Can only assume it is:

   |Multiplying thru with (x+1)(x-1)so as all denomimators=1

  3(x+1)-4(x-1)(x+1) = (x-1)

  3x+1-4(x^2-1)= x-1

   3x+1-4x^2+4 = x-1

   4x^2 -2x -6 = 0    |Note: standard format ax^2 + bx + c







   x = 12/8 = 3/2

   x = -8/8 = -1 

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