SOLUTION: find the roots of quadratic equations by factoring, x^2-6x+8

Question 431617: find the roots of quadratic equations by factoring, x^2-6x+8
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
If x2-6x+8=0, then
x2-6x+8=0
(x-4)(x-2)=0
The roots of your function are 4 and 2.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=4 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 4, 2. Here's your graph:

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