Solve the following systems: 2x - y = 1 6y - 2x = 9
Solve the following systems: 2x - y = 1 6y - 2x = 9 By substitution: Solve the first for y: 2x - y = 1 2x - 1 = y y = 2x - 1 Substitute (2x - 1) for y in the second: 6y - 2x = 9 6(2x - 1) - 2x = 9 12x - 6 - 2x = 9 10x - 6 = 9 10x = 15 x = 15/10 x = 3/2 Substitute 3/2 for x in y = 2x - 1 y = 2x - 1 y = 2(3/2) - 1 y = 3 - 1 y = 2 The solution is (x,y) = (3/2, 2) Edwin AnlytcPhil@aol.com
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