SOLUTION: Quadratic equations: Find two possitive numbers that differ by 2 and have a producy of 20. The answer is -1 + squareroot of 21 and 1 + squareroot of 21. How do I at the a

Question 4306: Quadratic equations:
Find two possitive numbers that differ by 2 and have a producy of 20.
The answer is -1 + squareroot of 21 and 1 + squareroot of 21.
How do I at the answer. (need steps)

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
First, assign the variables:
Let the two numbers be x and y
Then: x - y = 2 Rewrite as: x = y + 2 and substitute into the 2nd equation.
and xy = 20
(y+2)y = 20
y^2 + 2y = 20
y^2 + 2y - 20 = 0 Solve by use of the quadratic formula:

x = y + 2

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