Hi

solve the linear-quadratic system algebraically 

y= 5-x^2    |Note the use of ^ (uppercase 6)

y= x-15

 x-15 = 5-x^2

x^2 + x - 20 = 0

factoring

(x+5)(x-4)=0 Note:SUM of the inner product(5x) and the outer product(-4x) = x

(x+5)= 0  x = -5   y = -20   (-5,-20)

(x-4)=0   x = 4    y = -11   (4,-11)



 

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