SOLUTION: x2+7x+12=0

Question 424823: x2+7x+12=0
Found 2 solutions by linh117, shree840:
Answer by linh117(31) (Show Source): You can put this solution on YOUR website!
x2+7x+12=0
x^(2)+7x+12=0
For a polynomial of the form x^(2)+bx+c, find two factors of c (12) that add up to b (7). In this problem 4*3=12 and 4+3=7, so insert 4 as the right hand term of one factor and 3 as the right-hand term of the other factor.
(x+4)(x+3)=0
Set each of the factors of the left-hand side of the equation equal to 0.
x+4=0_x+3=0
Since 4 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 4 from both sides.
x=-4_x+3=0
Set each of the factors of the left-hand side of the equation equal to 0.
x=-4_x+3=0
Since 3 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 3 from both sides.
x=-4_x=-3
The complete solution is the set of the individual solutions.
x=-4,-3
Answer by shree840(260) (Show Source): You can put this solution on YOUR website!
x^2+7x+12=0
x^2+4x+3x+12=0
x(x+4)+3(x+4)=0
(x+3)(x+4)=0
x= -3,-4
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