SOLUTION: Please help with the following word problem. Thank you!! The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimens

Question 42460: Please help with the following word problem. Thank you!!
The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?

Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
length = 1 + w
width = w
Pythagoras Theorm:

a=2 b=2 c=-15

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=124 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2.28388218141501, -3.28388218141501. Here's your graph:

Answer:
length:
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