SOLUTION: Help me to solve:
10x^4 - 19x^2 + 6 = 0
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Question 423723: Help me to solve:
10x^4 - 19x^2 + 6 = 0
Found 2 solutions by stanbon, dnanos:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
10x^4 - 19x^2 + 6 = 0
---
10x^4-15x^2-4x^2+6 = 0
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5x^2(2x^2-3)-2(2x^2-3) = 0
----
(2x^2-3)(5x^2-2) = 0
----
Solve:
2x^2-3 = 0
x^2 = 3/2
x = +-sqrt(6)/2
----------------------
Solve:
5x^2-2 = 0
x^2 = 2/5
x = +-sqrt(10)/5
==============================
Cheers,
Stan H.
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Answer by dnanos(83) (Show Source): You can put this solution on YOUR website!
let x^2=y We have to find y and then x...
The general formula for is
Where a=10,b=-19, and c=6
=
=
=
We obtain two values for y:
y=3/2 or y=8/20=2/5=0.4
Each one of them gives two values for x:
x=
x=
or
x=-
or
x=
or
x=-
So we have four solutions:
;-;;-
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